阅读下列材料:
若1-3xx2-1=Ax+1+Bx-1,试求A、B的值.
解:等式右边通分,得A(x-1)+B(x+1)(x+1)(x-1)=(A+B)x+(-A+B)x2-1,
根据题意,得A+B=-3 -A+B=1
,
解之,得A=-2 B=-1
.
仿照以上解法,解答下题.
(1)已知x+6(x+1)(2x-3)=Mx+1-N2x-3(其中M、N为常数)求M、N的值;
(2)若1(2n-1)(2n+1)=a2n-1-b2n+1对任意自然数n都成立,则a=1212,b=1212;
(3)计算:11×3+13×5+15×7+⋯+12019×2021=1010202110102021.
1
-
3
x
x
2
-
1
=
A
x
+
1
+
B
x
-
1
A
(
x
-
1
)
+
B
(
x
+
1
)
(
x
+
1
)
(
x
-
1
)
=
(
A
+
B
)
x
+
(
-
A
+
B
)
x
2
-
1
A + B = - 3 |
- A + B = 1 |
A = - 2 |
B = - 1 |
x
+
6
(
x
+
1
)
(
2
x
-
3
)
=
M
x
+
1
-
N
2
x
-
3
1
(
2
n
-
1
)
(
2
n
+
1
)
=
a
2
n
-
1
-
b
2
n
+
1
1
2
1
2
1
2
1
2
1
1
×
3
+
1
3
×
5
+
1
5
×
7
+
⋯
+
1
2019
×
2021
1010
2021
1010
2021
【答案】;;
1
2
1
2
1010
2021
【解答】
【点评】
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发布:2024/8/5 8:0:8组卷:384引用:3难度:0.8